Retrieve the first 9 digits from the numeric value


 
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# 8  
Old 06-30-2008
And Z-Shell:

Code:
zsh-4.3.4% typeset -i n=000000001200820060734
zsh-4.3.4% print $n[1,9]
120082006

# 9  
Old 06-30-2008
another way
Code:
# n=100400001200820060734
# read -n 9 a <<<$n
# echo $a
100400001

# 10  
Old 07-01-2008
another option:
typeset -L9 a
a=<the number>
# 11  
Old 07-01-2008
Quote:
Originally Posted by cuitao
another option:
typeset -L9 a
a=<the number>
This is nice, I suppose it's ksh (ksh93?) feature (also supported by zsh)

Code:
zsh-4.3.4% typeset -L9 n=000000001200820060734
zsh-4.3.4% print $n
000000001

Given the OP requirement it should be (assuming integer value, of course):

Code:
zsh-4.3.4% typeset -iL9 n=000000001200820060734
zsh-4.3.4% print $n
120082006

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