Shell Programming and Scripting

Hi
I am running a 'grep' command to retrieve a line from the file. The problem is that I also need 21 lines which go right after the line I just 'grep'(ed)
Is there a way to retrieve this block of data? Thanks -A

Code:

awk '/pattern/{c=21;next}c&&c--' file

Regards

Hi
I am trying to retreive the line containing the pattern from a file and 21 lines right after this number by running the following awk command:
$ awk '/940/{c=21;next}c&&c--' allocations.ini and getting the following
syntax error:

$ awk '/940/{c=21;next}c&&c--' allocations.ini
awk: syntax error near line 1
awk: bailing out near line 1
$

any idea? Thanks -A

On Solaris use nawk.

also if you need to include the line containing a pattern:

Code:

nawk '/pattern/{c=22}c&&c--' file