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Can't interpret variable in if statement

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# 1  
Old 06-25-2008
Can't interpret variable in if statement
Can someone help me out here. I can't get this piece of code to work. i.e. $ALL_EVENTS does not get interpreted in the if brackets. The first part is the code, the second part is the execution of the code. Note: $ALL_EVENTS does equal 2, but there is no value once passed to the if statement.




echo $ALL_EVENTS

if [[ $All_EVENTS -eq 2 ]]; then
echo "it works"
fi




ALL_EVENTS= 2
+ echo 2
2
+ [[ -eq 2 ]]
# 2  
Old 06-25-2008
just try with this

if [[ "$All_EVENTS" -eq "2" ]]; then
echo "it works"
fi
# 3  
Old 06-25-2008
Quote:
Originally Posted by jwholey
echo $ALL_EVENTS

if [[ $All_EVENTS -eq 2 ]]; then
echo "it works"
fi

ALL_EVENTS= 2
+ echo 2
2
+ [[ -eq 2 ]]
Is All_EVENTS vs ALL_EVENTS a typo ?
# 4  
Old 06-25-2008
Sure was a type o. Thanks. There goes the first wasted hour of my day.
# 5  
Old 06-25-2008
typeset -i ALL_EVENTS
Placing this before the script should resolve the issue
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