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URG!! Last position of a character

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# 1  
Old 06-23-2008
Error URG!! Last position of a character
Hi.
If I have files with names like abcd.20080625.1234.abc.XYZ abcd.20080625.1234.abc.XYZW

how can I get the XYZ or XYZW part? is there something like an Index() function but in reverse order?
I was thinking that if I can get the position of the last dot (.) I can use substr, but i dont know how to get the last position of a character.

Thanks
# 2  
Old 06-23-2008
Shell solution.
Code:
a=abcd.20080625.1234.abc.XYZ
echo ${a#.*}

# 3  
Old 06-23-2008
Hammer & Screwdriver Will it always be after the 4th period "."?
Code:
>echo abcd.20080625.1234.abc.XYZ | cut -d"." -f5
XYZ
> echo abcd.20080625.1234.abc.XYZW | cut -d"." -f5
XYZW

# 4  
Old 06-23-2008
Quote:
Originally Posted by danmero
Shell solution.
Code:
a=abcd.20080625.1234.abc.XYZ
echo ${a#.*}


Tested shell solution:
Code:
  $ a=abcd.20080625.1234.abc.XYZ
$ echo ${a##*.}
XYZ
$

Smilie
# 5  
Old 06-23-2008
mmm no, the filename could have more than 4 periods. what I know for sure is that it will be after the last period.

Thanks.
# 6  
Old 06-23-2008
Quote:
Originally Posted by Perderabo
Tested shell solution:
Code:
  $ a=abcd.20080625.1234.abc.XYZ
$ echo ${a##*.}
XYZ
$

Smilie
Thanks !!

Does this works to find the x-ocurrence of a character? If i wanted the 3rd or the 6th position of the period?
# 7  
Old 06-23-2008
Try this:
Code:
$ cat looper
#! /usr/bin/ksh

a=abcd.20080625.1234.abc.XYZ

echo input = $a
while [[ -n $a ]] ; do
       if [[ $a = *.* ]] ; then
               piece=${a%.${a#*.}}
               a=${a#*.}
       else
               piece=$a
               a=""
       fi
       echo $piece
done
exit 0
$ ./looper
input = abcd.20080625.1234.abc.XYZ
abcd
20080625
1234
abc
XYZ
$
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