Shell Programming and Scripting

Hi !!! Dear People,
Please help me with the following problem.
consider this output:
Top 5 Timed Events
~~~~~~~~~~~~ Total
Event Waits Time (s) Ela Time
---------------------------- ------------ ----------- -----
CPU time 2,152 54.10
free buffer 7,059 641 16.10
control file parallel write 19,625 490 12.31
log file sync 7,010 217 5.44
db file sequential read 3,000 1000 .99
--------------------------------------------------------
we all know ,if i give
egrep '^(log file sync)...' /oracle/user_user/2
it will print
log file sync 7,010 217 5.44
please tel me how to print next line using egrep.
meaning... it should print immediate next line of pattern matching character(here it's log file sync).
my desired output should be
db file sequential read 3,000 1000 .99

perhaps with the same pattern matching character

please help me to give the command.
im using default shell(-sh)

Thanks in Advance

Line before is "-B", "line after" is "-A". One line after is "-A1", see 'man grep'.
If you want to see only the next line you could pipe that through 'tac|head -1'.

hay it's not working.. please give me full code......

Code:

awk '/^log file sync/{getline;print;exit}' file

Regards