Shell Programming and Scripting

Hi,

The above command does not seek to work.

I tried echo >> file
It is appending the newline at the end of file.

But can you help me in putting with a condition to check whether
if {newline does not exists at end of file}
then
echo >> file

Pls help me out with this.

Regards,
Krishna

Have you tried the awk solution?

Hi,

I got it working like this :
if [ -n "`tail -1c $file`" ]
then
echo >> $file
fi

This wil append new-line at the EOF if it does not exists.

I have some more file-level validation to take care. Need your valuable inputs on this.

My (comma-separated) file is something like below:

1.0,20080317081500,00001,00006,6
00001,20080317,00001,60213000071,2105,I
00002,20080317,00002,60213000071,0,D
00003,20080317,00003,60213000072,2104,I
00004,20080317,00004,60213000073,2103,I
00005,20080317,00005,60213000074,2102,I
00006,20080317,00006,60213000074,0,D
10.1.254.21

Ignoring first line and last line, I need to retrieve the last 3 fields of the other lines, for further validation. Copying these fields, to a separate file also is ok.

The new file can be:

60213000071,2105,I
60213000071,0,D
60213000072,2104,I
60213000073,2103,I
60213000074,2102,I
60213000074,0,D

Here i need to validate 2 points:
1. In each line, first field should have length equal to 11 and start with 60
2. In each line, last field should have either "D", "I" or "U" in it.


Pls let me know about this.

With Regards,
Krishna

Hi All,

Need someone's help urgently on this.

Pls let me know.

With Regards

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