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Shell Programming and Scripting

how to retrieve base name of the file

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# 8  
Old 06-13-2008
Using cut or IFS, as seen in another post, will only work for a fixed number of sub directories.

The solutions using basename, dirname, sed or variable expansion work for all directory depth.

^_^
# 9  
Old 06-13-2008
Power (to ripat) you are correct
My earlier solution would only work with the example file structure. SO, how about the following:

Code:
> cat another_shift 
A=/bb/data/f233pdb
fldb=$(echo $A | tr "/" "\n" | wc -l)
flda=$((fldb-1))
B=$(echo "$A" | cut -d"/" -f"$fldb")
C=$(echo "$A" | cut -d"/" -f1-"$flda")"/"

echo $A
echo $B
echo $C

and now the execution of those commands:

Code:
> another_shift 
/bb/data/f233pdb
f233pdb
/bb/data/

To see it working (I substituted on the first variable in the script):
Code:
A=/bb/data/another/level/f233pdb

> another_shift 
/bb/data/another/level/f233pdb
f233pdb
/bb/data/another/level/
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