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Quick question on grep: grabbing lines above and below

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# 1  
Old 05-27-2008
Quick question on grep: grabbing lines above and below
Just a quick question on grep/egrep.

I am writing a shell script that is looking for certain strings in a text file. It works well and gets exactly what I need.

However, the way the program writes to the text file, it puts the timestamp in a line above the string I am looking for and the path below the string I am looking for.

So my question is, how do I grab all three lines in my search? I am thinking I might need to go to something more powerful like awk.

I appreciate the help.

TCG
# 2  
Old 05-28-2008
In the basic implementations of grep, not without putting a lot of shell script round it. In newer version of grep, there's a commandline parameter to display a set number of lines before and after each match. man grep for more info and to see if you have the right version.
# 3  
Old 05-28-2008
Quote:
Originally Posted by Smiling Dragon
In the basic implementations of grep, not without putting a lot of shell script round it. In newer version of grep, there's a commandline parameter to display a set number of lines before and after each match. man grep for more info and to see if you have the right version.
Hmm. Ok. I will check it out.

On my particular system, we are running Solaris 9. Not sure if that would support the newer version.

Assuming that I do not have the newer version, any other suggestions?

Thanks.

TCG
# 4  
Old 05-29-2008
Can you show a bit of the file as example?
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