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counting no of argumnts passed to a function

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# 1  
Old 05-21-2008
Java counting no of argumnts passed to a function
hi
i have a function
abc()
{

//from this function i am passing some args to another function def()

}
def()
{
//Now i need to calculate the no of input args and iterate through them
}
please help
# 2  
Old 05-21-2008
u can use $# to get the number of arguments and then u can for loop to iterate the arguments
# 3  
Old 05-21-2008
Java counting no of arguments passed to a function
hi aju

i did like this
def()
{
number=$#

}

but it is giving no of agrs as 0(Zero)

Please help
# 4  
Old 05-21-2008
Code:
#! /usr/bin/ksh

fn1 ()
{
  echo "number of args in fn1 $#"
  fn2 $*
}

fn2 ()
{
  echo "number of args in fn2 $#"
}

fn1 A B C


output after running above script

Code:
$ 66022_functions.s
number of args in fn1 3
number of args in fn2 3

# 5  
Old 05-21-2008
Why are you posting the same question[1] again ?

[1] https://www.unix.com/shell-programmin...-function.html
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