using -exec in a script


 
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# 1  
Old 05-12-2008
using -exec in a script

I am using a third party job management program called Autosys. the command to load a jil into the autosys database is jil < somefilename.jil
I have a directory and it in are a lot of jils. rather than type jil < somefilename.jil for every file I would like to script something do do it. if cd to the dir and run the following command:
fin . -name "*.jil" -exec rm {} \;
it removes every .jil file in the dir. So with that rational i tried running this command to load the jil's:
find . -name "*.jil" -exec jil < {} \;
I figured it would perform jil < ...... for every .jil file in the dir, but it came back with this error:
A file or directory in the path name does not exist.
ksh: {}: 0403-016 Cannot find or open the file.
any ideas what I am doing wrong?
# 2  
Old 05-12-2008
try this or you can try xargs:
Code:
find . -name '*.jil' -type f | \
while read file 
do
       jil < $file
done

# 3  
Old 05-12-2008
wow, that worked. Thanks a lot. you really helped out a jr.jr.jr admin
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