Shell Programming and Scripting

I do not know much about shell scripting and need to create a script and I am at a loss. If someone can help me, that would be great!!

I have two directories:

/dir1

/dir2


I need to get the sequence number which is part of the filename in /dir1 and delete all files in /dir2 that are less than that sequence number and have the same ending number extension. Example:


/dir1/1_400_123456


/dir2/1_400_123456
/dir2/1_399_123456
/dir2/1_398_123456
/dir2/1_300_999999




So, I would need to look in the /dir1 directory and see the sequence number is 400. Then, in the dir2 directory, I need to delete any files that are less than 400 and have the same '123456' ending number. So the only files in /dir2 left would be:


/dir2/1_400_123456
/dir2/1_300_999999



Thanks in advance if you can help in anyway!

Try this script, if you get the expected output you can pipe the output to sh to remove the files.

Code:

#!/bin/sh

cd /dir2

ls /dir1 > tmp1
ls /dir2 > tmp2

awk 'BEGIN {FS=OFS="_"}
NR==FNR{a[$3]=$2;next}
$3 in a{if(a[$3]<=$2){next}}
{print "rm "$0}
' tmp1 tmp2

rm tmp1 tmp2

Regards

Thanks for your help! It looks like this is almost there. It is listing all of the files that have a sequence number lower than what is found in the first directory. But, it looks like it is not comparing the next node of the file:

/dir1/1_400_123456


/dir2/1_400_123456
/dir2/1_399_123456
/dir2/1_398_123456
/dir2/1_300_999999


The script is listing:

/dir2/1_399_123456
/dir2/1_398_123456
/dir2/1_300_999999


Even though the second node of the file is lower in the /dir2/1_300_999999 file, it should not delete this file because the next node is different.

I looked over something, try this:

Code:

#!/bin/sh

cd /dir2

ls /dir1 > tmp1
ls /dir2 > tmp2

awk 'BEGIN {FS=OFS="_"}
NR==FNR{a[$3]=$2;next}
$3 in a{if(a[$3]>$2){print "rm "$0}
'  tmp1 tmp2

rm tmp1 tmp2

Regards

It works! Thank you!!!