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How to get 07 while giving ((Preyy = yy - 01))

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# 1  
Old 05-08-2008
How to get 07 while giving ((Preyy = yy - 01))
Hi,

I need to get the previous year as 07 instead of just 7. I'm running the following for this..

yy=`date '+%y'`
((Preyy = yy - 01))
echo ${Preyy}

Here, instead of 07 i'm getting 7 as result. Please Help.

Thanks,
RRVARMA
# 2  
Old 05-08-2008
MySQL Yes i got it...
i just added this in between...

Preyy=$(printf "%02d" $Preyy)


and now my script goes lik this..

yy=`date '+%y'`
((Preyy = yy - 01))
Preyy=$(printf "%02d" $Preyy)
echo ${Preyy}

Thanks,
RRVARMA
# 3  
Old 05-08-2008
Quote:
Originally Posted by RRVARMA
Hi,

I need to get the previous year as 07 instead of just 7. I'm running the following for this..

yy=`date '+%y'`
((Preyy = yy - 01))
echo ${Preyy}

Here, instead of 07 i'm getting 7 as result. Please Help.

Thanks,
RRVARMA
Code:
#!/usr/bin/ksh
yy=`date '+%y'`
prev=0$(( yy - 1 ))
echo $prev

# 4  
Old 05-08-2008
Best way to do this

Code:
typeset -R2Z Preyy

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