Shell Programming and Scripting

Hi,
We have a file with a unit seperator as the delimeter.

Here are the Sample lines from the file:

ASIA/PACIFICHong KongFX2007071080900
ASIA/PACIFICHong KongFX2007071080900/ 800129HK

This delimeter has the ascii value of \037.
I have to strip the second feild in this file for which i m
using the cut command as follows:
lines=`cat ibia.txt | cut -d "" -f2`
and this works for me.

But i just want to confirm if it is the
correct way to proceed or should we try to do the same with Ascii value
or is there any other better means of handling it.
I tried with Ascii value and i get "bad delimeter". Please help.

Thanks in advance,
Sudha.

If it works, it's correct. :-)

However you may prefer to make it more readable, perhaps this:

Code:

lines=`awk -F '\037' '{print $2}' ibia.txt`

Thanks a lot. But giving ascii value does'nt work thats y I gave the delimeter directly.

It may not work with cut, but it does work with awk, at least for me.

Hi,
I have a simple code as follows:
Percent_fail=`echo "scale=6; $Col_nm_cnt / $Line_cnt_lan" | bc`

Though I get the answer correcly as follows, I also get an error msg along with it as follows:
.333333
./test.ksh[14]: .333333: unexpected `.'

Can anyone please help me how to avoid this error message and why i get this message

Thanks in advance,
Sudha.