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Shell Programming and Scripting

printing each users by processes

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Top Forums Shell Programming and Scripting printing each users by processes
# 8  
Old 04-28-2008
Quote:
Originally Posted by sam4now
firstname.surname firstname.surname firstname.surname
Ah, right, for me it prints the username, which is more straightforward to process.

Would this work any better?

Code:
#!/bin/bash
users | tr ' ' '
' | sort -u | while read user
do
  echo $user
  ps -U `grep ":$user[,:]" /etc/passwd | cut -f1`
done

I simply pass through the dot in the full name since it matches any character (including, conveniently, space) in a regular expression.
# 9  
Old 04-28-2008
pls can u explain this part of the code

`grep ":$user[,:]" /etc/passwd | cut -f1
# 10  
Old 04-28-2008
what i really want is their name and each individual processes such as

joe bloggs
PID TTY TIME CMD


peter jackson
PID TTY TIME CMD

baba mama
PID TTY TIME CMD
# 11  
Old 04-28-2008
wasn't something similar answered here?
# 12  
Old 04-28-2008
yeah
but i dont know about awk yet and i dont want to use things i am not fully aware of, am just reading about it.
I would love to find other means in getting the desired output.

Thanks
# 13  
Old 04-28-2008
We grep for ":" because that's the separator in the passwd file, followed by the user name, followed by either another colon, or a comma, because many passwd files have gcos fields after the user's name. My entry looks like this:

Code:
era:x:1000:1000:era,,,:/home/era:/bin/bash

The commas would properly separate room number, phone number etc information.

Oops, the cut -f1 should be cut -d: -f1 of course.
Last edited by era; 04-28-2008 at 07:13 PM.. Reason: Just noticed cut should have -d : option
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