Shell Programming and Scripting

Hi,
I should read a number situated just after "= " symbole in a line from a file and put it in a variable.
the line in file is :
number of transaction=7

and I should put 7 in a variable (7 or other values), then
read the file :


And then how to select just the number after = symbole :

myvariable2=????

Thanks for help.

If the text you want to analyze is in a variable already:

Code:

myvariable2=${othervar#*=}

This produces the value in othervar with anything up to the first equals sign removed.

If it's coming from a file which contains a single line:

Code:

myvariable2=`cut -d = -f2- otherfile`

There's a myriad different ways to split a file on a particular separator but cut is very simple and easy to understand. You could also do this with sed, awk, perl, or even grep (if you are a bit clever, and trust there to be exactly one equals sign in the file).

If there are multiple lines and you want the one with "number of transactions", try awk or sed:

Code:

myvariable2=`awk -F = '/number of transactions/ { print $2 }' otherfile`

Note that the backquote characters are "grave" ones (ASCII 96), not regular apostrophes.

hi big123456.
hint:

Code:

myvariable=$(echo "number of transaction=7" | cut -d= -f2)

Regards.

Thank to all.
era :
more otherfile
dfffffffffh fnjfjfjk ,kkkfkk
number of transaction=7
fffffffffffff fffg fhhfj k
mmf h ddddjj gggkjgk


My script (big.sh) :
myvariable2=`awk -F = '/number of transactions/ { print $2 }' otherfile'
echo $myvariable2

And now :

# ./big.sh
./big.sh: line 1: unexpected EOF while looking for matching ``'
./big.sh: line 3: syntax error: unexpected end of file


Thanks for help.

You seem to have replaced the final backquote with a regular apostrophe; it's probably better if you copy+paste the code from above in order to get the punctuation right.

Also, I carelessly put in "transactions" in plural; you will need to drop the final s. Sorry about that.

It was that.
Many many thanks.