Shell Programming and Scripting

code_0_0=1001
code_0_1=Test1
code_1_0=1002
code_1_1=Test1

x=1001

while [ $i -le 1 && $x -ne $code_$i_0 ]
do
i=`expr i + 1`
done

echo The Value Matched at $i variable and has value $code_$i_1

First, you haven't initialized $i.

Then, there are two problems in the test statement. The first is the attempt to use an indirect variable.

If you are using bash, you can build the name of the variable and use the ! expansion:

Code:

iv=code_${i}_0
val=${!iv}

For other shells (and for portability), use eval:

Code:

eval "val=\$code_${i}_0"

In both of the above examples, note the braces around the 'i' to prevent the variable being interpreted as $i_0.

You cannot use && inside a test expression; either use -a or two separate test commands:

Code:

while [ $i -le 1 -a $x -ne $val ]

Or:

Code:

while [ $i -le 1 ] && [ $x -ne $val ]