Shell Programming and Scripting

I have file (srv_lst) with the contents as ...

9.2 IRMD115
8.1 IRMD115

and I am using the sort as to get the bigger version as :

sort -r -u +1 $srv_lst | sort -k 1,1r

and the output is 9.2 which is good ..

if I have the contents of file srv_lst as :

9.2 IRMD115
10.2 IRMD115

and using the same sort function : sort -r -u +1 $srv_lst | sort -k 1,1r

the out put is 9.2 again .

what am I doing wrong here ..

Thanks

Try :

Code:

sort -r -u +1 $srv_lst | sort -k 1,1rn

Jean-Pierre.

Thankyou for the reply .

It's not working . still same output .

Thanks

Works fine with my cygwin sort :

Code:

$ cat sort.dat
9.2 IRMD115
10.2 IRMD115
1.1 XYZ
11.12 ABC
0.0 Y
10.2 IRMD116
$ sort -r -u +1 sort.dat | sort -k 1,1rn
11.12 ABC
10.2 IRMD116
9.2 IRMD115
1.1 XYZ
0.0 Y
> sort -k 1,1rn -u sort.dat
11.12 ABC
10.2 IRMD115
9.2 IRMD115
1.1 XYZ
0.0 Y
>

Jean-Pierre.

What exactly are you trying to do. Why do you need the -u option to sort.

Code:

sort -k1,1nr srv_lst   # sorts srv_lst in reverse numerical order based on the 1st column