Shell Programming and Scripting

Hi ....
Iam having the file ....in which 3rd column is numerical having 8 decimal part... i want that to cut to 2 decimal part ...

Source File :

E100|0|19940.10104030|0|1ABC
E103|1|19942.10195849|3|0ABC
E100|0|19943.10284858|0|1ABC

I want to be ......

Reulst:

E100|0|19940.10|0|1ABC
E103|1|19942.10|3|0ABC
E100|0|19943.10|0|1ABC


Please help me .......

Code:

awk 'BEGIN{OFS=FS="|"}
{
 $3=sprintf("%.2f",$3) 
}1' file

Thanks yaar . Hi it is working fine.

if iam having 5th 9th column's also having the decimal numbers like earlier the same code can use ???

below is corr

awk 'BEGIN{OFS=FS="|"}
{
$3=sprintf("%.2f",$3) $5=sprintf("%.2f",$5) $9=sprintf("%.2f",$9)
}1' file.txt

put them on separate lines!

Iam confused ....
can you give me exact code please ...........