Shell Programming and Scripting

Hi All,

My query is as below:

Am basically writing a parser script.
My input file has got some variables which are populated by the calling program.

callig program:

fun1("cat","dog","cow")

input.*
argument[1] first
argument[2] second

I want to write a script that should give me the result as below when executed:

first="$1"
second="$2"

Forget about the calling function but the script i guess can be done using a for loop or a while, both am not at all comfortable with.

Can some one please help me in this.
Sorry for making the query so complicated.

Thanks in advance
JS

Am working on the same .. I came across the below query in awk.The fir loop is mentioned here just for the logic to understand.


for(i=0;i<=6;i++)
{
awk '/param/ {print $2"=\"$""\"" }' a.txt > we.txt
}

I want the we.txt to look like
first="$1"
second="$2"

Using my query i can print only
first="$"
second="$"

How can i print the value of "i "inside the awk statement using the for loop or while ????
This is what i tried to explain above

Thanks
JS

okay, i didnt understand your first post, but i think you need to pass i as a parameter inside awk.. so here goes:

for(i=0;i<=6;i++)
{
awk -v value_of_i=$i '/param/ {print $2"=\"$"value_of_i"\"" }' a.txt > we.txt
}

Hello ag79,

Thanks a lot for ur time.I ran the following query

for i in 1 2 3
do
awk -v value_of_i=$i '/param/ {print $2"=\"$"value_of_i"\"" }' a.txt > we.txt
done

But this gav me the result

first="$3"
second="$3"
third="$3"


but my out put should be

first="$1"
second="$2"
third="$3"

Is this possible?

Thanks
JS

Hi All,

I found a solution :

a=1
awk '/param/{a++;print $2"=\"$" a"\""}' a.txt > we

Thanks
JS