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How to match the last XML extension by using Case statement

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# 1  
Old 04-05-2008
How to match the last XML extension by using Case statement
Hi All,

I have a status.txt file which contains following three files.

1.xml
2.xml
3.xml

Now i have written a shell script 1.sh which contains the following

cat status.txt | while read filename
do
echo $filename
case "$filename" in
xml)
echo "running 1.xml"
;;
esac
done

now when i am running the above 1.sh file then i am getting the following output.

1.xml
2.xml
3.xml

But i am not getting the following output
running 1.xml
Can anybody told me that what is the wrong with this 1.sh code??

Should i check the /xml$/ for case statement??????

Thanks
# 2  
Old 04-05-2008
Hi sunitha,
use this.

cat status.txt | while read filename
do
echo "here $filename"
case "$filename" in
*xml)
echo "running 1.xml"
;;
esac
done
# 3  
Old 04-05-2008
Also lose the Useless Use of Cat.

Code:
while read filename
do
  echo "here $filename"
  case "$filename" in
    *xml)
      echo "running $filename"  # ... I guess you mean
      ;;
  esac
done <status.txt

# 4  
Old 04-06-2008
Thanks
Hi javeed7/era,

Thanks a log.
Yes it is working absolutely fine.
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