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# 1  
Old 04-04-2008
awk slash
I have configuration file(master.cnf), that contents are:
VER1LOG /src/ver1/log
VER2LOG /src/ver2/log
APPLOG /src/sys/apps/log
APPCONF /src/sys/apps/conf
APPBIN /src/sys/apps/bin

my shell script is as below
mylog=sys/apps

awk "/$mylog/" master.cnf
awk: syntax error Context is:
>>> /sys/apps <<<

in the above example I want to print First field that maches with $mylog
here I used variable mylog, the value of mylog contains "/" charcter, this is same as char used in awk
to specify PATTERN.When I try as above it thors an error
so my requirement is i need to use variable, the value of varibale can contain the "/" char.
and how can I get the desired result?
Regards
# 2  
Old 04-04-2008
Code:
awk -F/ -v var=$mylog '$0 ~ var{print $1}' master.cnf

Regards
# 3  
Old 04-06-2008
Bug
Thanks it works for me,
What does -F/ -v var=$mylog '$0 ~ var{print $1} do?

Regards,
Naresh
# 4  
Old 04-06-2008
awk issue with slash, multiple FS
Now the requirement is different with different input file(master.cnf)
>cat master.cnf
/usr| location for usr|5
/src/ver1| version 1 |10
/src/ver2/log| ver 2 log |25
/src/sys/apps/log| Application log for sys|36
/src/sys/apps/conf| configuration location for app|45
/src/sys/apps/bin| binary location app|55
Code:
my shell script is as below:
mylog=/usr
awk -F/ -v var=$mylog '$0 ~ var{print $2}' master.cnf
result is :
usr| location for usr|5

I need only second filed separated by | should be displayed. i.e “location for usr” should be displayed

Code:
Another script is :
mylog=/src/ver1
awk -F/ -v var=$mylog '$0 ~ var{print $2}' master.cnf
result is: 
src
but I need “  version 1 “ to be displayed

to summary the requirements:
1. should be able to use variable, the value of variable can contains multiple “/” chars
2. need to print the second filed separated by “|”
Thanks
# 5  
Old 04-06-2008
Code:
awk -F '|' '{print $2}'

-F indicates the separator. The more elaborate trick was a clever workaround to avoid the need to backslash-escape the separator chararcter (which would be the plain-jane solution when the separator character is also a special character).
# 6  
Old 04-09-2008
Quote:
thanks for the response
now i want to try to search with different field.

the data file is as below:
Code:
> cat master.cnf
/usr| location for usr|5
/src/ver1| version 1 |10
/src/ver2/log| ver 2 log |25
/src/sys/apps/log| Application log for sys|36
/src/sys/apps/conf| configuration location for app|45
/src/sys/apps/bin| binary location app|55

my script is as below:
>
Code:
desc='Application log for sys'
>echo $desc
Application log for sys
> awk -F '|' -v var=$desc '$0 ~ var{print $3}' master.cnf

Code:
output is 
input file "for"input file "sys"input file "$0 ~ var{print $3}"
/usr| location for usr|5
/src/ver1| version 1 |10
/src/ver2/log| ver 2 log |25
/src/sys/apps/log| Application log for sys|36
/src/sys/apps/conf| configuration location for app|45
/src/sys/apps/bin| binary location app|55

Quote:
I need to print field 3 separated by "|" and I want to use varibale to seach , the value of variable can contin the space char.
Please suggest me
# 7  
Old 04-09-2008
The only change you need is to quote the variable (to cope with spaces).

Code:
awk -F'|' -v var="$desc" '$0 ~ var{print $3}' master.cnf

If you get error messages you do not understand, post them here; they do mean something, and help us see what's wrong.
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