Shell Programming and Scripting

Hi all, I need to write a script "hunt" that is similar to "find" without using "find" in there. Also have to print out how many subdirectories it's got.
like if I type:

Code:

$hunt unix

it will show:

Code:

2 /home/var/unix

something like that. I have no idea how to do the file search without using find command and how to count to number of subdirectories. I don't need the whole code, just someone give me some clues please? Just let me know how to implement it. Thanks in advance!

You can do something like that :

Code:

[ $# -ne 1 ] && exit 1

if [ -d "$1" ]
then
   directory=$1
else
   directory=$(dirname "$1")
   if [ ! -d "$directory" ]
   then
      echo "$0 - directory not found : $1"
      exit 1
   fi
fi


echo $(ls -lR "$directory" | grep ^d | wc -l) $directory

Jean-Pierre.

Thank you so much for the help!