Shell Programming and Scripting

Hi all,

Just subscribed to this forum. Not a regular user of Unix.

I did the following:
We have a directory structure /a/b/c5/

Where c5 is the only directory inside b.
export ANOOP=/a/b/c*/
echo $ANOOP=/a/b/c5/

I have to create a symbolic link to anoop.txt in the directory /a/b/c5/d/.

ln -s $ANOOP/d/anoop.txt $ANOOP/d/anoop1.txt

ln: creating symbolic link `/a/b/c*/d/anoop1.txt` to `/a/b/c5/d/anoop.txt` : No such file or directory


When I tried echoing "$ANOOP/d" the whole path was printed(/a/b/c5/d), however when i tried to echo a non existing file in the same path it couldnt convert c* into c5. Which might have been the issue for the above link issue also.

echo $ANOOP/d/anoop1.txt=/a/b/c*/d/anoop1.txt.

Could any of you help me figure out any way to tackle this particular issue.

The wildcard is expanded when you echo it, not when you assign it. Try adding those backticks which I otherwise always try to persuade people to avoid.

Code:

ANOOP=`echo /a/b/c*/`
set | fgrep ANOOP   # verify what's set without possibly expanding it

Thanks a Lot era. My issue is solved. I could succesfully create the link.