Shell Programming and Scripting

I wanted a perl script to be done for Password search & replace in two files.

For Example:

Example 1)--i am having a file such as
cat /opt/customer/Ariba/UAT/ariba/app/buyer/Server/config/Parameters.table

Example 2)--and i am having a other file in other location such as cat /opt/customer/home/username/CMStaging/UAT-20080304/AR/ServerFiles/opt/customer/Ariba/UAT/ariba/app/buyer/Server/config/Parameters.table

the example 1 file contains the string as **REPLACE**
the example 2 file contains the live password to be replaced.

i want is it should take the live password from the example 2 file & replace that (**REPLACE**)string with the example 1 file.

can anyone help me out for some code in detailed for the same on a urgent basis..

Thanks
Samir

Searching for a string in file and replacing it could be done very easily with "sed", look at the forum base for various examples. Why you want this in perl ? You're gonna have to open the file, search / grep for string, then replace and close the file - uncecessary long.

Perl can do this just like sed using perls inplace editor.

How do you find the "live password" in the second file?

actually i have 2 files
example

first file contains the live password in it & the second file contains **REPLACE** string

after running the script it should automatically take the password from the live file & replace that string of **REPLACE** in the second file

the same should be done for Multiple strings..

Please help...

Thanks
Samir

You need to answer my question above and provide more details. The generic answer is get the password from the file it's in, search the other file for the pattern and replace it with the password:

s/\Q**REPLACE**\E/$password/;