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# 1  
Old 03-06-2008
Lightbulb count character
Hi, I am reading a string from a file.
now i want to count the number of chareacter in the string and if it is more then 8 capture only last 8 characters.


ex. string=mypassword

<<do something>>

output should be:

string=password



Thanks for you help.
# 2  
Old 03-06-2008
Which shell?

With bash:

Code:
$ (("${#string}">8))&&string="${string: -8}"
$ printf "%s\n" "$string"
password

# 3  
Old 03-06-2008
you can use wc, standard tool in most *nix
Code:
# printf $string | wc -c
10

# 4  
Old 03-06-2008
I am sorry. I am using korn shell.

Quote:
Originally Posted by radoulov
Which shell?

With bash:

Code:
$ (("${#string}">8))&&string="${string: -8}"
$ printf "%s\n" "$string"
password

# 5  
Old 03-06-2008
Quote:
Originally Posted by myguess21
I am sorry. I am using korn shell.
Which one?

Code:
print {.sh.version}

or (if the above is null):

Code:
print $KSH_VERSION
# or
what $(which ksh)

# 6  
Old 03-06-2008
sorry not able to find the ksh version.

i tried all three command.
# 7  
Old 03-06-2008
Perhaps something like this?

Code:
echo "string=mypassword"|awk 'BEGIN{FS=OFS="="}{$2=substr($2,length($2)-7)}1'

Regards
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