Shell Programming and Scripting

#! /bin/sh

grep -n $1 $2

#! /bin/sh
##This script I simplified to pseudo code...  I have the correct math ##syntax
##in the file and it works.... I just can't remember it offhand! :(
a=$1*$1
b=$2*$2
c=$3*$3
ab=a+b
ac=a+c
bc=b+c

*insert pythagorean checks here*

#! /bin/sh
for file in $*; do
        if [ -f "$file" ]; then
        {
                index=`expr $index + 1`
                chars=`wc -c $file | cut -d' ' -f1`
                words=`wc -w $file | cut -d' ' -f1`
                lines=`wc -l $file | cut -d' ' -f1`

                echo "$file data:"

                echo "$chars characters"
                echo "$words word"
  	        echo "$lines lines"
  	        echo " "
         }
         else
        {
                echo "$file does not exist"
        }
        fi

done

while getopts 2>/dev/null r c
do
# only accept -r as a valid command otherwise display help.
  case $c in
    r) find . -type f | xargs ls -la |cut -c35-45,59-120 \
       | sort -r -n  ; exit 0 ;;
   \?) echo "\nUsage: $0 [-r]
       list the byte count and name of files in current dir sorted by size
       -r recursively lists all of the subdirectories as well" >&2
        exit 2;;
  esac
done

while getopts r:f:c: o
do case "$o" in
  r) 
    myvariable="right.s"
    anothervariable="0"
    i put more code here
    even more code  here;;
  f) myvariable=findtext.s;;
  c) myvariable=count.s;;
  ?) *help like message*
esac
done

 grep -n $1 $2

f)grep -n $1 $2

grep -n $x $x+1