Shell Programming and Scripting

i want to take position 19-24(only first line) from all files and need to compare any duplication is there or not.
If duplication, then i have to print the file names.


I have written to take the characters from 19-24 from all files. but how to compare ?

fPath='/lacbibs/out/files/prod_fixes'

for in_filename in `ls -rt $fPath/*CTR*`
do
slBankId=`head -1 $in_filename| cut -c 19-24`
echo "$in_filename : $slBankId "
done


Output of the above script is :

/lacbibs/out/files/prod_fixes/P.207.20080221.dat : 103415
/lacbibs/out/files/prod_fixes/P.208.20080221.dat : 103420
/lacbibs/out/files/prod_fixes/P.209.20080221.dat : 103424
/lacbibs/out/files/prod_fixes/P.210.20080221.dat : 103415
/lacbibs/out/files/prod_fixes/P.211.20080221.dat : 103432
/lacbibs/out/files/prod_fixes/P.212.20080221.dat : 103436
/lacbibs/out/files/prod_fixes/P.213.20080221.dat : 103441


The below two files are having same string. i want to display these two filenames.
/lacbibs/out/files/prod_fixes/P.207.20080221.dat
/lacbibs/out/files/prod_fixes/P.210.20080221.dat


can anyone help on this.

Thanks in advance.

Redirect the output of "echo" in your for loop to a file called "outfile" and append following code to your code.

while read one_line
do
field=`echo "$one_line" | cut -d: -f2 | cut -c2-`
if [ `grep -c $field outfile` -gt 1 ]
then
echo "$one_line" | cut -d" " -f1
fi
done < outfile