Shell Programming and Scripting

I need to extract the character before the last "|" in the following lines, which are 'N' and 'U'. The last "|" shouldn't be extracted. Also the no.s of "|" may vary in a line, but I need only the character before the last one.

TT-CAP-N241485-0005241485|ADMINISTRATOR|INC_ORGANISATION_NAME|SUPERIOR_TITLE_1|REV|FIRST_NAME_1|MIDDLE_NAME_1|SURNA ME_FIELD|INC ADDRESSS 1|INC ADDRESSS 2|INC ADDRESSS 3|INC ADDRESSS 4|INC ADDRESSS 5|INC ADDRESSS 6|IN123EC|MALTA|Y||M||Y|LIFEASSURED 2|Y|N||||||||||||||||||||||||Y||Y||||||||||||PRU|A||289832|||FCBGFBF|Y|Y|1|DC|1|1|3|Y|O||20300601||| CAP|5649369|VVUMU7SMT0|HCBCBFDJF|N|Y|N|Y|Y|N|Y|Y|N|3||6|C|20051205|555555555|||||20070604|4|15||C|0| 9|4527|0||20071109|4|C|982062|23569837|36657407|9096||20071205|1|N|

TT-CAP-5241492-0005241492|ADMINISTRATOR1|INC_ORGANISATION_NAME|SUPERIOR_TITLE_1|MS|FIRST_NAME_1|MIDDLE_NAME_1|SURNA ME_FIELD|INC ADDRESSS 1|INC ADDRESSS 2|INC ADDRESSS 3|INC ADDRESSS 4|INC ADDRESSS 5|INC ADDRESSS 6|IN123EC||N||F||N|LIFE ASSURED 1|Y|N||||||||||||||||||||||||Y||Y||||||||||||PRU|BFF||200006|||EB|Y|Y|3|DC|2|1|3|Y|O||20301207|||CAP |5649376|ZLBFQDGVGIOIJDHKNDK|F|N|Y|Y|N|Y|N|N|Y|N|4||7|C|20051205|555555555|||||20070604|2|1600770||B |281215|66|124002|923545||20060405|1|C|1446100|92811|64148521|5||20071205|1|U|

I'm not able to achieve it by cut command. How can it be done ?

With awk you can set the fieldseperator to "|" and print the "last field - 1".

Regards

Edit:

Just saw that this is a duplicated post of this:

https://www.unix.com/shell-programmin...-one-char.html