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remove part of a line

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# 8  
Old 02-06-2008
Hi Vino
I tried your code. However, it doesn't solve my grep problem.

Do you have any other solution?

Thanks
# 9  
Old 02-06-2008
cat file | grep proc | awk -F"$" '{ print $1 }'
# 10  
Old 02-06-2008
Hi All
I have just realized that beside removing anything after $$, I also need to remove anything before the file name.

That is, if my file has the following:
/foldera/database/procedure/a.proc$$/version1/2
/folderb/database/procedure/proj1/b.proc$$/version2/2

I hope to have the following result:
a.proc
b.proc

I have tried using unix "cut" command, but I am no where getting the result I wanted... could someone please give me some example...I am really stucked.

Thanks
# 11  
Old 02-06-2008
Quote:
Originally Posted by tiger99
Hi All
Thank you all for your help. I am using cut, because it's easier to understand for me


I have an issue with grep before pipe the result to get the $$.. removed.

I have
grep ".proc" file.txt | cut ....

From my understanding, it should only return lines with .proc
However, I am not getting how come the following line also gets returned?

/vobs/aw/database/proc/Account$$/main

Can someone help me, how can I modify my grep so that only something like a.proc or b.proc get returned ?

Thanks
That's because the "." stands for any character and grep matches it to the slash that comes before proc (/proc). To match "." escape it so that it loses its special meaning...

Code:
grep "\.proc" file.txt | cut

# 12  
Old 02-06-2008
Quote:
Originally Posted by tiger99
Hi Vino
I tried your code. However, it doesn't solve my grep problem.

Do you have any other solution?

Thanks
What is your grep problem ?

If your input is

Code:
/vobs/aw/database/proc/Account$$/main
/foldera/database/procedure/a.proc$$/version1/2
/folderb/database/procedure/proj1/b.proc$$/version2/2

then the expected output is
Code:
a.proc
b.proc

Right ?

Try this

Code:
sed -n -e "s/.*\/\([^\/]*\.proc\)\$\$.*/\1/p" input.txt

# 13  
Old 02-06-2008
cat file | cut -d "$" -f1
# 14  
Old 02-06-2008
Can u try this one out........

while read a
do
echo $a | awk -F"." '{print $1".proc"}'
done < filename
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