Shell Programming and Scripting

Good morning,
Sir's i would like to ask for help regarding to my awk and loop problem, a script that will check my files a and b then if it will see there was a time below 3am it will echo the file that contains below 3am file, for this example it will redirect the file a to an output.
$ cat a
Sun Feb 3 08:49:01 EAT 2008
Sun Feb 3 12:09:33 EAT 2008
Mon Feb 4 01:44:48 EAT 2008
Mon Feb 4 13:02:00 EAT 2008

$cat b
Sat Feb 2 08:14:34 EAT 2008
Sat Feb 2 09:55:36 EAT 2008
Sun Feb 3 08:44:13 EAT 2008
Sun Feb 3 09:46:38 EAT 2008
Mon Feb 4 07:43:09 EAT 2008
Mon Feb 4 09:41:24 EAT 2008

desired output:
file a has below 3 am.

Thanks

Try...

Code:

awk -F '[ :]' '$4+0<n{printf "File %s below %s\n", FILENAME, n}' n=3 a b

Do you have to use awk here? This will work too:

Code:

while read one two three four rest; do 
   if [ ${four%%:*} -lt 3 ]; then 
      echo file a has below 3 am; 
      break; 
   fi; 
done < a
while read one two three four rest; do 
   if [ ${four%%:*} -lt 3 ]; then 
      echo file b has below 3 am; 
      break; 
   fi; 
done < b

If you have a lot of files, you can loop for each file too.

great! thanks to all