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how to get last value in an array in perl

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# 1  
Old 02-04-2008
how to get last value in an array in perl
Hi,

I have a set of file names say:

file1
file2
file3
..
filen

I may just do a ls -l or however it works to read this list into an array...

I need to pick the last file name that is "filen" from the list...

your help is greatly appreciated.....hope im clear on my question...
# 2  
Old 02-04-2008
Code:
zsh-4.3.4% ls
file1  file2  file3  file4  file5
zsh-4.3.4% perl -le'print $ARGV[-1]' file*
file5

# 3  
Old 02-04-2008
Code:
ls file* | sort | tail -1

Smilie
# 4  
Old 02-04-2008
Quote:
Originally Posted by V3l0
Code:
ls file* | sort | tail -1

Smilie
Or Smilie

Code:
$ ls
file1  file2  file3  file4  file5
$ set -- file*;echo $_
file5

P.S. For some shells it should be:

Code:
set -- file*
echo $_

Last edited by radoulov; 02-04-2008 at 12:03 PM.. Reason: corrected
# 5  
Old 02-04-2008
wow.. thanks for the really quick replies.. im doing this using a script tmp.pl ..

$ ls
file1 file2 file3 file4 file5
$ set -- file*;echo $_
file5

can u please tell me how to write this in a script??? thanks again
# 6  
Old 02-04-2008
If it's a perl script, use perl:

Code:
zsh-4.3.4% ls
file1  file2  file3  file4  file5  temp.pl
zsh-4.3.4% cat temp.pl 
#!/usr/bin/perl 
use warnings;

@files = <file*>;
print "$files[-1]\n"; 
zsh-4.3.4% ./temp.pl 
file5

# 7  
Old 02-04-2008
i have got a solution ... its little different but it works.....

my @files = glob("file*");
my $last_file_name = pop(@files);

thanks for ur quick replies again........
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