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Pattern matching in file and then display 10 lines above every time

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# 22  
Old 04-09-2009
Quote:
Originally Posted by Franklin52
With awk:

Code:
awk '/total/{c=10;next}c-->0' file

Regards

Thanks Franklin52
Sorry for the streching the thread.. as iam new bie in the Unix....

with the above command it starts printing 10 lines below the line with total, so if i wish to print that line with total also what needs to be done.......
Regards
# 23  
Old 04-09-2009
Quote:
Originally Posted by digitalrg
Thanks Franklin52
Sorry for the streching the thread.. as iam new bie in the Unix....

with the above command it starts printing 10 lines below the line with total, so if i wish to print that line with total also what needs to be done.......
Regards
This should print the line with total and 10 lines after that line:

Code:
awk '/total/{c=11}c-->0' file

Regards
# 24  
Old 04-09-2009
Thank you very much.... Smilie

Regards.....
# 25  
Old 04-10-2009
Hi Franklin52
Sorry to extend again... if i want to introduce a line of
=============================================
after every 10 lines of pattern total what shall i do ?

Thanks
# 26  
Old 04-10-2009
Quote:
Originally Posted by digitalrg
Hi Franklin52
Sorry to extend again... if i want to introduce a line of
=============================================
after every 10 lines of pattern total what shall i do ?

Thanks
Something like this?

Code:
awk '/total/{c=11}c-->0{print;if(c==0){print "======"}}' file

# 27  
Old 04-10-2009
Thanks Franklin this didnt work.. no difference.. in the output
# 28  
Old 04-10-2009
Quote:
Originally Posted by KevinADC
I know sethcoop is trying to help but his perl code is not well written, here is what you want to do:

Code:
#!/usr/bin/perl
use strict;
use warnings;
my $lines = 10;
open(F, "file.txt") or die "cannot read file";
while(<F>) {
  if (/total/)  {
      print scalar <F> for (1..$lines);
      last;
  }
}
close(F);

borrowed from awk
Code:
line: while (<>) {
    if (/line 5/){ $c = 5; next line; }
    print $_ if $c-- >0 ;
}
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