Shell Programming and Scripting

Fine. So what is it that you are facing ?

if [[ "${option1}" == "purge" && ${option_count} -eq 3 && -n "${option2}" && -n "${option3}" ]]
then

echo " in the purge if block"
else

echo " in the else part of purge since parametrs are empty"


when there are 3 parameters and 2 of them are empty then it needs to go the else part and display the echo message.But it shows the scho message in the first if block.

The condition is not getting statisfied.

Can't you just rely on option_count and forget the quote, i mean
just sampleshellscript archive instead of sampleshellscript archive ' ' ' ' ;
Isnt that the simplest way ?

i need to call a Oracle stored procedure from shell script.

So if i know there are 3 parameters that are to be passed i want to make

sure that these are not empty.based on count i can only know there are 3

parameters but how can i make sure they are not empty.

hummmm... how about this one

Code:

purge_block()
{
echo "I'm purging ..."
}
[[ $# -eq 3 && -n $1 && -n $2 && -n $3 ]] && purge_block && exit

echo here goes else where ...

the above conditon is for null values but it does not work for empty strigs

like ' ' i.e single qote start and then ten spaces then end single quote.