Split a Big Report.


 
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# 8  
Old 01-22-2008
Its working fine for me, and am not having any SUN os to check

Still we will try

awk -F ':' '{
if($0 ~ "^Report No")
{
fl=1;
i=0;
}
if(fl==1)
{
data[i]=$0;
i++;
}
if($0 ~ "^BE NO:")
{
fname = "reprot_"$2".lis";
gsub(" ","",fname);
for(j=0;j<i;j++) print data[j] > fname;
fl=0;
}
else if(fl==0)
print $0 > fname;
}' Report.txt


For this script can u tell me in which line ur getting error
# 9  
Old 01-22-2008
Quote:
Originally Posted by ranjithpr
Still we will try

awk -F ':' '{
if($0 ~ "^Report No")
{
fl=1;
i=0;
}
if(fl==1)
{
data[i]=$0;
i++;
}
if($0 ~ "^BE NO:")
{
fname = "reprot_"$2".lis";
gsub(" ","",fname);
for(j=0;j<i;j++) print data[j] > fname;
fl=0;
}
else if(fl==0)
print $0 > fname;
}' Report.txt


For this script can u tell me in which line ur getting error
test: awk -F ':' '{
> if($0 ~ "^Report No")
> {
> fl=1;
> i=0;
> }
> if(fl==1)
> {
> data[i]=$0;
> i++;
> }
> fname = "reprot_"$2".lis";
> gsub(" ","",fname);
> for(j=0;j<i;j++) print data[j] > fname;
> fl=0;
> }
> else if(fl==0)
> print $0 > fname;
> }' Report.txt

error message:
awk: syntax error near line 1
awk: bailing out near line 1
# 10  
Old 01-22-2008
use nawk or /usr/xpg4/bin/awk for solaris...not awk for this style of coding :-)
# 11  
Old 01-22-2008
Try this one, and let men know the error line

awk 'BEGIN {FS=":"}
{
if($0 ~ "^Report No")
{
fl=1;
i=0;
}
if(fl==1)
{
data[i]=$0;
i++;
}
if($0 ~ "^BE NO:")
{
fname = "reprot_"$2".lis";
gsub(" ","",fname);
for(j=0;j<i;j++) print data[j] > fname;
fl=0;
}
else if(fl==0)
print $0 > fname;
}' Report.txt
# 12  
Old 01-22-2008
Quote:
Originally Posted by ranjithpr
awk 'BEGIN {FS=":"}
{
if($0 ~ "^Report No")
{
fl=1;
i=0;
}
if(fl==1)
{
data[i]=$0;
i++;
}
if($0 ~ "^BE NO:")
{
fname = "reprot_"$2".lis";
gsub(" ","",fname);
for(j=0;j<i;j++) print data[j] > fname;
fl=0;
}
else if(fl==0)
print $0 > fname;
}' Report.txt
error message:
awk: syntax error near line 3
awk: illegal statement near line 3
awk: syntax error near line 13
awk: illegal statement near line 13
awk: syntax error near line 16
awk: illegal statement near line 16
awk: syntax error near line 20
awk: illegal statement near line 20
# 13  
Old 01-22-2008
Hi Tytalus,

Would you mind to tell me how to use the nawk in Solaris? Thanks
# 14  
Old 01-22-2008
hi ranjithpr,

When I try to use nawk in my Solaris, the following code is fine for me.

nawk -F ':' '{ if($0 ~ "^Report No") {fl=1; i=0;}
if(fl==1){data[i]=$0; i++;}
if($0 ~ "^BE NO:")
{
fname = "reprot_"$2".lis";
gsub(" ","",fname);
for(j=0;j<i;j++) print data[j] > fname;
fl=0;
}
else if(fl==0) print $0 > fname;
}' Report.txt

But I find the first reprot_111.lis got error....
the expert result should be:

report_111.lis

Report No.: AAA

BE NO: 111

asfsdflsjdfklsdjfklsjfklsfsflsjdlk
fsdfjsfkjsklfsfj

Report No.: AAA

BE NO: 111

sdfsdfjsdklfjsfkj
fsdflkjsdfklsjkl

BUT I got the following result:
report_111.lis
Report No.: AAA

BE NO: 111

asfsdflsjdfklsdjfklsjfklsfsflsjdlk

fsdfjsfkjsklfsfj

Would you mind, please check it for me? (I will check it by myself as well) Thanks.
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