How to print arguments along with spaces using awk

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01-17-2008

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Quote:

Originally Posted by radoulov

Code:

awk 'sub(/^aaa/,"")' filename

I'm not sure if you want the space after the pattern (if any),
in that case:

Code:

awk 'sub(/^aaa */,"")' filename

HI radoulov,

Thank you for the reply ..
Finally i have made it as given below :

awk 'sub(/^('"${name}"')/,"")'

Regards,
JS

jisha

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01-17-2008

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Thank you Yogesh ..

jisha

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