How to print a value in the variable using awk ?

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01-14-2008

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How to print a value in the variable using awk ?

Hi All,

I have a part of a script below:

var1="value1"
awk 'BEGIN {printf("%36s \n ","value1")}'

Instead of directly giving the "value1" , I need to give using "var1" in the above awk statement.

Is this possible?
If so, what is the modified awk command?

Thanks in advance
JS

jisha

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01-14-2008

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Same logic that the other example:

Code:

awk 'BEGIN {printf("%36s \n ","'"${var1}"'")}'

Klashxx

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