Shell Programming and Scripting

Dear Sirs,

I want to cut the IP address from the following text line:

"[1] mgmt.mib-2.bgp.bgpPeerTable.bgpPeerEntry.bgpPeerLastError.163.121.170.20 (OctetString): 0x04 00"

I want to get the (163.121.170.20) only.


Thanks in advance.

in shell:

echo "[1] mgmt.mib-2.bgp.bgpPeerTable.bgpPeerEntry.bgpPeerLastError.163.121.170.20 (OctetString): 0x04 00" | cut -d . -f 7- | cut -d " " -f 1

dunno if you want more than that, sometimes you have to say what you want, rather than thinking about what you think is the good solution for your problem and ending up with a loop of problems

GNUawk

Code:

# more file
[1] mgmt.mib-2.bgp.bgpPeerTable.bgpPeerEntry.bgpPeerLastError.163.121.170.20 (OctetString): 0x04 00
#awk '{b=gensub(/.*[. ]([0-9]+\.[0-9]+\.[0-9]+\.[0-9]+).*/,"\\1","g",$0);print b}' file
163.121.170.20

Zouhair,
Thank you very much, It works well.

Hi,

Code:

echo "[1] mgmt.mib-2.bgp.bgpPeerTable.bgpPeerEntry.bgpPeerLastError.163.121.170.20 (OctetString): 0x04 00" | sed '
s/.*\.\([0-9]\{1,3\}\.[0-9]\{1,3\}\.[0-9]\{1,3\}\.[0-9]\{1,2\}\).*/\1/'

isn't it easier to use "... | cut -d'.' -f7-10"?

bakunin

No, because then you will have the rest of the string:
zouhair@gutzy:~ (.318 MB) $ echo "[1] mgmt.mib-2.bgp.bgpPeerTable.bgpPeerEntry.bgpPeerLastError.163.121.170.20 (OctetString): 0x04 00" | cut -d . -f 7- | cut -d " " -f 1
163.121.170.20
zouhair@gutzy:~ (.318 MB) $ echo "[1] mgmt.mib-2.bgp.bgpPeerTable.bgpPeerEntry.bgpPeerLastError.163.121.170.20 (OctetString): 0x04 00" | cut -d . -f 7-10
163.121.170.20 (OctetString): 0x04 00
zouhair@gutzy:~ (.318 MB) $