A way to use test for "$x" = [a-z] (regex)


 
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# 1  
Old 12-15-2007
A way to use test for "$x" = [a-z] (regex)

In bourne, I was hoping to do:

if test "$x" = [a-z]

but even when x equals "q" (not with quotes) test returns 1.

Is there a way to do this?
# 2  
Old 12-15-2007
For regular expressions I normally use case....

Code:
case "$x" in
[a-z] )
        echo lowercase
        ;;
* )
        echo not lowercase
        ;;
esac

# 3  
Old 12-15-2007
Thanks. I'll try that
# 4  
Old 12-15-2007
Hmm, how do I create a regular expression for NOT [a-z]? In Bourne, [^a-z] gave me an error message:

expr: unmatched [ or [^

The ultimate goal is to test that $x is one character, no more no less, and is [a-z]
# 5  
Old 12-15-2007
Really easy:

Code:
case "$x" in
  [a-z]) echo "I don't want this because it's lowercase";;
  * ) echo "Yippee! It's not lowercase";;
esac

Smilie
# 6  
Old 12-15-2007
Quote:
create a regular expression for ...
You're using globbing, not regular expressions Smilie
# 7  
Old 12-15-2007
Quote:
Originally Posted by radoulov
You're using globbing, not regular expressions Smilie
Isn't globbing to do with filenames?
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