Shell Programming and Scripting

I know I am new to this forum and I dont want to rock the boat but.......

this is your third thread about this problem, sorry but it sounds like a homework problem.

if it is a homework problem then this may not be the best place to look for answers.

if you need this for work them you may be out of your depth in your job, if your job needs shell scripting skills then you may have a big learing curve.

you cant expect people on the forum to give you a finished script to solve your problems.

I hope I havent over stepped the mark....

I think the deadline is looming as well.

Porter,

This is great! I am making significant progress. Here is the new code:

Code:

#!/bin/sh

while true; do
cat <<ENDINPUT

Menu of Options

1. Display all files in a user's home directory
2. Welcome yourself to the program
3. Display System Information
4. Exit back to Windows

ENDINPUT
echo Please enter your choice:
read option
case "$option" in

1)
   ls -l
   ;;
2)
   echo welcome
   ;;
3)
   uname -a
   ;;
4)
   exit
   ;;
*)
   echo "Use 1, 2, 3, or 4"
   ;;
esac
done

Now, when I select Option #4 it does not exit the program. I need to shut down the connection completely and return to Windows. Right now, it's just going to my home directory.

Gee, thanks for the input robs.

A while back in an earlier post I asked what does "Exit to Windows" mean?

What does an AIX box know or care about you and Windows?

It means that executing/choosing that option quits the connection to the Unix server, closes the command prompt window, and returns the user to the Windows desktop.

Assuming your script is called "menu.sh" and is in the current directory AND you have the while true/do/done loop setup.

then try...

Code:

. ./menu.sh

or

Code:

exec ./menu.sh

However, on an AIX box I would not have an option that says Exit to Windows because AIX has no control over what client you are calling from. If I use ssh from a Macintosh, should I still see "Exit to Windows"?