Shell Programming and Scripting

Hello,

I've the follwing text:

gfdgfg
--------------------------------
dfgfdgdfg
fdgfdgfdgdgf
fdgf
------------------------------
f
g
gdgf
a constant string that i know
---------------------------------------------
data I want to have data I want to have
data I want to have data I want to have
....
data I want to have data I want to have
data I want to have data I want to have
----------------------------------------------
fdgfdg
fdgfdgd
fdgfdg
---------------------------------
dsfgfdgfdg
dsfgfdgfd
dfsg
-----------------------------------
sfdgfdgf
fdgfdg




I want to get the text between the rows ------------------------
Before this there is a known constant String.
I've tried with sed, but with no result. I've the problem that
there are mutiples textparts between the rows --------------------

Any ideas?

Thanks a lot,
Eric

Code:

awk '/start_pattern/,/end_pattern/ { print }' filename

Hy matrixmadhan,

is it with awk possible to create a pattern over 2 rows?

best regards, Eric

Something like this:

Code:

awk '/^---/{f=0}/constant/{getline;f=1;next}f' filename

Use nawk or /usr/xpg4/bin/awk on Solaris.

can you post sample input and output ?

Hy,

Input is like the my first post and output should be only the bold text.
or in ohter words

I know the string from the first line, so i think the startpattern have to find

Known_string\n
--------------------------------------------------------


the end pattern have to find the next row with
--------------------------------------------------------

But the row with
--------------------------------------------------------
occurs multiple times in the text

Can I match this with awk or sed ?

Best regards, Eric

somewhat ugly, but......
nawk -f eric.awk myFile

eric.awk:

Code:

BEGIN {
  PAT="constant string"
}

$0 ~ PAT {f=1;print;next}
f && /^--*$/ {b=1;print;next}
b,/^--*/
{f=0;b=0}