Shell Programming and Scripting

Thanks but I am afraid it is also not working..

showing the below error
cat: cannot open /tmp/I_out.plt20546


Now I am doing like this

Code:

I_plt=/tmp/I_out.plt$$
Q_plt=/tmp/Q_out.plt$$
 
plot(){
  echo "#!/usr/local/bin/gnuplot -persist" > /tmp/"$1"_out.plt$$
  echo "plot \"$1_indat.txt\" " >> /tmp/"$1"_out.plt$$
  
 }

  plot I
  cat $I_plt 
  plot Q
  cat $Q_plt

But I think there should be a better way to doing this ..

Thanks for your help..

What shell are you using?

korn shell

Hi,

Previously, you encountered the error [cat: cannot open /tmp/I_out.plt20546] for the simple reason that the file - /tmp/I_out.plt20546 - mentioned in the first line of your code was NOT being created. The plot function was redirecting output to I_plt in the current working directory and not in /tmp.

I believe the following code should work:

I_plt=/tmp/I_out.plt$$
Q_plt=/tmp/Q_out.plt$$

plot(){
echo "#!/usr/local/bin/gnuplot -persist" > /tmp/$1_out.plt$$
echo "plot \"$1_indat.txt\" " >> /tmp/$1_out.plt$$
}

plot I
cat $I_plt
plot Q
cat $Q_plt


Do let me know
- Sandy0077

Dear Sandy ,

Thank for your reply.. But Sandy you can see my previous quote much similar to you.. Anyway thanks a lot again..

user_prady
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