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Print last occurrence if first field match

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# 8  
Old 11-18-2007
awk
HI,

code:

Code:
awk '
{
out[$1]=$0
}
END{
for (i in out)
print out[i]
}' filename

# 9  
Old 11-19-2007
Quote:
Originally Posted by summer_cherry
HI,

code:

Code:
awk '
{
out[$1]=$0
}
END{
for (i in out)
print out[i]
}' filename

Hi Summer,
Your code is able to work but some how the sequence of display seems to be jumbled up. " 0004 " should be at the last line but it came to the 1st line.

Below is my output using your code:

$ awk -f myawk data

0004 k= 6
0001 k= 27
0002 k= 1
0003 k= 1
# 10  
Old 03-13-2008
Hi vgersh99,

If i need to capture the 1st occurrence instead that is if column1 of row1 equals to column1 of row2 then the whole line of column1 row1 is being printed out , how can i modify your code below to fulfill this requirement?

Code:
$1 != prevIDX && FNR != 1 { print prev}
{ prevIDX=$1; prev=$0 }
END { print prev }

Input:

0001 k= 1
0001 k= 26
0001 k= 27
0002 k= 1
0003 k= 1
0004 k= 1
0004 k= 4
0004 k= 5
0004 k= 6

Output:

0001 k= 1
0002 k= 1
0003 k= 1
0004 k= 1
Last edited by Raynon; 03-13-2008 at 08:07 AM..
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