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Help using IFS to break up a record (ksh)

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Top Forums Shell Programming and Scripting Help using IFS to break up a record (ksh)
# 1  
Old 11-01-2007
Help using IFS to break up a record (ksh)
I have a program that produces output similar to this:

Code:
 16010001pe3m_313101.ver
 16010001pe3m_313101.ver

 16010001pe4m_0
 16010001pe4m_0

 16010001pe4m_1
 16010001pe4m_1

 16010001pe4m_313101.ver
 16010001pe4m_313101.ver

 group_defs.txt
 Group Definition File

I have a ksh script where I am trying to get it to print like this:

Code:
16010001pe3m_313101.ver 16010001pe3m_313101.ver
16010001pe4m_0              16010001pe4m_0
16010001pe4m_1              16010001pe4m_1
16010001pe4m_313101.ver 16010001pe4m_313101.ver
group_defs.txt                   Group Definition File

Here is what the code looks like:

Code:
	typeset -L80 relative_path
	typeset -L80 description
	typeset -i count=0
	OFS=IFS
	IFS='
'
	for i in $(program)
	do
		print $i
	done

So I need to get two lines into two separate variables, and I need iterate through the loop when a blank line is encountered.

I've tried using...

Code:
IFS='
'
while read var1 var2
do
  print $var1 $var2
done < $(program)

But that doesn't work either.

How do you set IFS to a blank line?

Suggestions welcome.

Thanks.
# 2  
Old 11-01-2007
One way, assuming the blank lines are just a carriage return:
Code:
awk '{              
        if( len($0) )
             { print $0 }
        else
              {printf("%s ", $0) }
        END{ print }
       }' filename > newfilename

# 3  
Old 11-01-2007
nawk -f lyon.awk myFile.txt
lyon.awk:
Code:
BEGIN {
  FS=RS=""
}
{
  for(i=1; i<= NF; i++)
    printf("%-80s%s", $i, (i==NF) ? "\n" : "")
}

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