Shell Programming and Scripting

Hi guys,i got this problem which is..i need to find those sentences with date inside and extract them out,the input is somehow like this

eg:
$DATA42.GANTRY2.GA161147 DISKFILE 2007-10-16 11:56:45 SUPER.OPR \NETS.$Y4CB.#IN
\NETS.4,246
F DENIED READ

Report date range........: 2007-08-01 00:00 to 2007-08-01 23:59
Subject System...........: *
Subject Userid...........: *.*
Subject Login Name.......: *
Subject Terminal.........: *
Operation................: *

so what i need is the one with the date format (yyyy/mm/dd):
$DATA42.GANTRY2.GA161147 DISKFILE 2007-10-16

this line will be printed..can this be done using sed or awk????

chck if this is what you want:

Code:

grep '[[:digit:]]\{4\}-[[:digit:]]\{2\}-[[:digit:]]\{2\}' filename

Hi Yoguesh,well can this be done by awk or sed?i only got this two program..thanks alot!

GNU awk

Code:

awk --re-interval  '
/[[:digit:]]{4}-[[:digit:]]{1,2}-[[:digit:]]{1,2}/ && !/Report/{print}' file

output:

Code:

$DATA42.GANTRY2.GA161147 DISKFILE 2007-10-16 11:56:45 SUPER.OPR \NETS.$Y4CB.#IN

i leave it to you to remove the part starting from the time till the end. give it a try

Hi ghostdog,ya i managed to get the 2007-10-16 11:56:45 SUPER.OPR by using the following code

Code:
awk "/\$DATA.*DISKFILE/{print $3,$4,$5}" zyx.txt>zzz1.txt

Thanks alot for your help!!will need some more soon