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DateTime Format Conversion in a File

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# 1  
Old 10-17-2007
DateTime Format Conversion in a File
Hi Pals.

I have a file which is in the below format.

2007/10/15-12:04:24,'CRLift','TH-42PX75U','BestBuy','W01P0207',22,15,'User1'
2007/10/15-12:04:26,'CRLift','TH-42PX75U','BestBuy','W01P0207',22,15,'User2'
2007/10/15-12:04:29,'CRLift','TH-42PX75U','BestBuy','W01P0207',22,15,'User3'
2007/10/15-12:04:22,'CRLift','TH-42PX75U','CircuitCity','W01P0207',22,15,'User1'
2007/10/15-12:04:34,'CRLift','TH-42PX75U','CircuitCity','W01P0205',22,15,'User2'
2007/10/15-12:04:45,'CRLift','TH-42PX75U','CircuitCity','W01P0206',22,15,'User3'
2007/10/15-12:04:25,'CRLift','TH-42PX75U','CircuitCity','W01P0202',22,15,'User4'


All the fields are delimeted by "," comma

I need to convert the first field time format to MM/DD/YYYY HH24:MI:SS
Which is required later to load from SqlLoader.

Present format is YYYY/MM/DD-HH24:MI:SS
Required Format is MM/DD/YYYY HH24:MI:SS



Please Help me out...
Quick Response would be very helpfull...

Thanks & Regards
SrikGR.
Last edited by srikanthgr1; 10-17-2007 at 12:32 PM..
# 2  
Old 10-17-2007
One way:
Code:
#Present format is YYYY/MM/DD-HH24:MI:SS
#Required Format is MM/DD/YYYY HH24:MI:SS

awk -F, '{
           split($1,dateval, "-")
           split(dateval[1], date, "/");
           value=sprintf("%s/%s/%s %s",date[2],date[3],date[1],dateval[2])
           printf("%s",value)
           for(i=2; i<=NF;i++)
                {printf(",%s", $i)};
           printf("\n");
        }' filename

Code:
# output
10/15/2007 12:04:24,'CRLift','TH-42PX75U','BestBuy','W01P0207',22,15,'User1'
10/15/2007 12:04:26,'CRLift','TH-42PX75U','BestBuy','W01P0207',22,15,'User2'
10/15/2007 12:04:29,'CRLift','TH-42PX75U','BestBuy','W01P0207',22,15,'User3'
10/15/2007 12:04:22,'CRLift','TH-42PX75U','CircuitCity','W01P0207',22,15,'User1'
10/15/2007 12:04:34,'CRLift','TH-42PX75U','CircuitCity','W01P0205',22,15,'User2'
10/15/2007 12:04:45,'CRLift','TH-42PX75U','CircuitCity','W01P0206',22,15,'User3'
10/15/2007 12:04:25,'CRLift','TH-42PX75U','CircuitCity','W01P0202',22,15,'User4'

# 3  
Old 10-17-2007
sed
Hi,
This one should be ok for you.

Code:
echo 2007/10/15-12:04:24 | 
sed 's/\([0-9][0-9][0-9][0-9]\)\/\([0-9][0-9]\)\/\([0-9][0-9]\)\(-\)\(.*\)/\3\/\2\/\1 \5/'

# 4  
Old 10-23-2007
This wil be simple


for file in `cat bb`
do
var=`echo $file | cut -d"-" -f1`
var2=`echo $file | cut -d"-" -f2`
var3=`echo $file | cut -d"-" -f3`
value1=`echo $var | cut -d"/" -f1`
value2=`echo $var | cut -d"/" -f2`
value3=`echo $var | cut -d"/" -f3`
echo $value2"/$value3""/$value1""-$var2".$var3
done
# 5  
Old 10-23-2007
Hey Pals..
Thanks for the help..
Each of the above replies helped me and also vgersh sent out a another reply to this thread..
I would post that as that might be helpfull to another one like me...

nawk -f sri.awk a.dat

sri.awk:

Code:
BEGIN {
  FS=OFS=","
  SEPs="[-/:]"
}
{
  split($1, a, SEPs)
  $1 = a[2] "/" a[3] "/" a[1] " " a[4] ":" a[5] ":" a[6]
  print
}

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