Shell Programming and Scripting

Dear all,
i have a file which contains this lines.
0-0 CC=1
0-01
0-011
0-0111
0-01110 F=500 CC=1 L=15
M=5
TRD=3948
0-0112
0-01124
0-011240 F=33 L=18
M=8
PR=2
0-011241 F=33 L=16
M=6
PR=2
0-011242 F=500 L=15
M=5
TRD=3967
0-011243 F=500 L=15
M=5
TRD=3967
0-011244 F=500 L=15
M=5
TRD=3967
0-011245 F=500 L=15

i want to parse the file and want to get the output like

0-0~CC=1
0-01~
0-011~
0-0111~
0-01110~F=500 CC=1 L=15
~M=5
~TRD=3948
0-0112~
0-01124~
0-011240~F=33 L=18
~M=8
~PR=2
0-011241~F=33 L=16
~M=6
~PR=2
0-011242~F=500 L=15

this

so can any body plz help me how to do this?

Regards,
Thanks,
Panksj

What pattern does the output follow ?

Is it ?

Lines containing a - will have ~ soon after that word is over
Lines not containing a - will have a ~ at the beginning.

Code:

sed -e "s/^\([^-]*\)$/~\1/g" -e "s/\([^-]*-[0-9]*\)/\1~/g;s/~ /~/g"  sample.txt

Dear vino,
Thnax for ur reply but its not that what i want.
actually i want something like that
if one line contains only one number of field and having space before that field then the space will be replaced by the ~
if one line contains more that two field then ~ will be replaced between $1 (first field)and $2(second field) and the rest will be as it is...
this is what i want to do...
if line 1 contains
Mo12345
i want to replace that with

~Mo12345

if one line contains

00-01 cc=1

then output will be

00-01~cc=1

if one line contains

00-012 mrfm cc=1 L=15

then the output will be

00-012~mrfm cc=1 L=15

like this way

Thanks,
Regards,
Pankaj