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Shell Programming and Scripting

Processes and Users

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# 15  
Old 10-03-2007
Code:
#!/bin/ksh

w | nawk 'NR>2{print $1}' | sort -u | while read userID
do
   while IFS=: read userIDpasswd junk junk junk userName junk
   do
      if [ "${userID}" = "${userIDpasswd}" ]; then
         echo "userID->[${userID}] userName->[${userName}]"
      fi;
   done < /etc/passwd
done

# 16  
Old 10-03-2007
thx again, its work, but i am not allowed to use awk Smilie

there must being a simpler way to view logged in users and what processes they are running Smilie
# 17  
Old 10-03-2007
Sorry if I caused confusion on what I am trying to achieve
1) I need to find out users currently logged on to the system.
2) I need to find out what processes they are running.
3) I need to print those processes on the screen, for each user along with their actual name.
I am assuming the only way to get the name at this point if from the “/etc/passwd” file
Can this be done without using SED or AWK?
# 18  
Old 10-03-2007
Quote:
Originally Posted by barbus
this is the last task I have to do then I am no longer a trainee ^^, which means I can use whatever utility I want. :O
Quote:
Originally Posted by barbus
Can this be done without using SED or AWK?
Sounds like a strange game you are playing.
# 19  
Old 10-03-2007
Quote:
Originally Posted by barbus
thx again, its work, but i am not allowed to use awk Smilie

there must being a simpler way to view logged in users and what processes they are running Smilie
Code:
w | cut -d ' ' -f1 | sort -u | while read userID
do
   while IFS=: read userIDpasswd junk junk junk userName junk
   do
      if [ "${userID}" = "${userIDpasswd}" ]; then
         echo "userID->[${userID}] userName->[${userName}]"
      fi;
   done < /etc/passwd
done

# 20  
Old 10-03-2007
Quote:
Originally Posted by barbus
Sorry if I caused confusion on what I am trying to achieve
1) I need to find out users currently logged on to the system.
2) I need to find out what processes they are running.
3) I need to print those processes on the screen, for each user along with their actual name.
I am assuming the only way to get the name at this point if from the “/etc/passwd” file
Can this be done without using SED or AWK?
Look into what's been provided so far and also 'man who' and 'man w' - good luck!
# 21  
Old 10-03-2007
Quote:
Originally Posted by porter
Sounds like a strange game you are playing.
I did ask why I can’t use SED and AWK, the answer I got and I quote “we want our trainee's to learn more about the operating system to start with, and when we feel that you’re comfortable with basics, you will receive training with more advanced utilities from our IT team.”

These exercises I was give are the guide lines on how ready I am apparently.


trying it with who and w now.

thank
Last edited by barbus; 10-03-2007 at 06:00 PM..
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