Shell Programming and Scripting

Hi all,
When parameters are passed to the shell script, they are dereferenced by their position. For example,
I call myTest.sh and pass two parameters param1 and param2 as following:
./myTest.sh param1 param2

In the script, myTest.sh, I refer to first parameter (param1 ) as $1 and second parameter (param2) as $2.

Is there any way to make parameter passing independent. Something like
./myTest.sh -Dparameter1=param1 -Dparameter2=param2


Thanks,
Sonal.

Perhaps this.

Code:

[/tmp]$ cat try.ksh
#! /bin/ksh
#

while [ $# -gt 0 ] 
do
    key=${1%=*}
    case $key in
        "-Dparameter1") echo "Param1=[${1#$key=}]" ;;
        "-Dparameter2") echo "Param2=[${1#$key=}]" ;;
    esac
    shift;
done
    
[/tmp]$ ./try.ksh -Dparameter1="something" -Dparameter2="more"
Param1=[something]
Param2=[more]
[/tmp]$ ./try.ksh -Dparameter2="more" -Dparameter1="something"
Param2=[more]
Param1=[something]
[/tmp]$

You can add more flags within the case-esac construct.