Shell Programming and Scripting

Hey, I am very new to scripting and could use a bit of help.

I have a situation where I have an ascii file and I want to delete all lines beneath a particular string.

EXAMPLE:

The contents of a file named example.txt looks like the following:

JANUARY
FEBRUARY
MARCH
APRIL
MAY
JUNE
JULY
AUGUST
SEPTEMBER
OCTOBER
NOVEMBER
DECEMBER

Now I want to be able to run a command where it will delete all lines in the example.txt file beneath the "JUNE" line. I assume that this is pretty easy to do, but given my lack of experience I am having trouble figuring this out.

Is sed the answer? If so, what would the exact command be given my example?

The system I will run the command on is a Solaris 10 base install system with no 3rd-party packages installed.

Thank you in advance!

- LaLonde

Click here for a UNIX.COM search for SED

This solution is specific to this file alone:


sed -e '1,5d' -e '7,12d' FileName

OR You can use this solution also


sed -e '6!d' FileName

You can use any of the two--

cat file1
JANUARY
FEBRUARY
MARCH
APRIL
MAY
JUNE
JULY
AUGUST
SEPTEMBER
OCTOBER
NOVEMBER
DECEMBER


sed -e '1,6!d' file1
or
sed -e '7,12d' file1

Thanks
Namish

row_num=grep -n June filename|cut -d ":" -f1

row_num=6 After execution

then

haed -6 filename

Code:

sed "1,/JUNE/!d" example.txt