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Shell Programming and Scripting

Remove part of the file

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# 8  
Old 08-22-2007
awk 'BEGIN {ORS=RS="</product>";FS=">"}{if(substr($5,14,13)!="Application2<")print}' file
this shd work i beleive
# 9  
Old 08-22-2007
Thanks Ahmed, it works very well. I understand that we are removing the block, but can you throw me some light how this works.
Another problem is, for example I have two Application2 blocks with location1 and location2, is it possible to only delete location1 block?

Regards,
Chiru
# 10  
Old 08-22-2007
Quote:
Originally Posted by ahmedwaseem2000
Code:
awk 'BEGIN {ORS=RS="</product>"}{if(substr($5,14,13)!="Application2<")print}' file

Your code is not working
It works fine, I don't have any problem with it, do you?

Regards
# 11  
Old 08-22-2007
Quote:
Originally Posted by chiru_h
Thanks Ahmed, it works very well. I understand that we are removing the block, but can you throw me some light how this works.
Another problem is, for example I have two Application2 blocks with location1 and location2, is it possible to only delete location1 block?

Regards,
Chiru
here it is:

Code:
sed -n '
/<product\>/ b block
H
$ b block
b
:block
x
/location1.*Application2/ !p'
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